(-3y^2+y-2)=(5y^2+6y+7)

Solution for (-3y^2+y-2)=(5y^2+6y+7) equation:

(-3y^2+y-2)=(5y^2+6y+7)

We move all terms to the left:

(-3y^2+y-2)-((5y^2+6y+7))=0

We get rid of parentheses

-3y^2+y-((5y^2+6y+7))-2=0


We calculate terms in parentheses: -((5y^2+6y+7)), so:

(5y^2+6y+7)

We get rid of parentheses

5y^2+6y+7

Back to the equation:

-(5y^2+6y+7)


We get rid of parentheses

-3y^2-5y^2+y-6y-7-2=0

We add all the numbers together, and all the variables

-8y^2-5y-9=0

a = -8; b = -5; c = -9;
Δ = b2-4ac
Δ = -52-4·(-8)·(-9)
Δ = -263
Delta is less than zero, so there is no solution for the equation